WMA11 June 2021

7.​​ WMA11/01 Edexcel​​ IAL P1 June 2021 Q7​​ (Straight Line Graphs &​​ Radians)

x=0

The line l1​​ has equation 4y + 3x = 48​​ 

The line l1​​ cuts the y-axis at the point C, as shown in Figure 3.​​ 

(a) State the y coordinate of C.​​ 

(1)

The point D(8, 6) lies on l1.​​ The line l2​​ passes through D and is perpendicular to l1​​ 

The line l2​​ cuts the y-axis at the point E as shown in Figure 3.​​ 

(b) Show that the y coordinate of E is​​ -143​​ 

(3)

A sector BCE of a circle with centre C is also shown in Figure 3.​​ 

Given that angle BCE is 1.8 radians,​​ 

(c) find the length of arc BE.​​ 

(3)

The region CBED, shown shaded in Figure 3, consists of the sector BCE joined to the triangle CDE.​​ 

(d) Calculate the exact area of the region CBED.​​ 

(3)

SOLUTION​​ 

a-​​ 

Method # 01

Point C is the y-intercept of line​​ l1. So let us arrange the equation of line​​ l1​​ to get y-cordinate of point C.

4y+3x=48

4y=-3x+48

y=-34x+484

y=-34x+12

Hence, the y-intercept of line​​ l1​​ or​​ the y-coordinate of point C is 12.

Method # 02

Point C is the y-intercept of line​​ l1. So put x=0 in the equation of line​​ l1.

4y+3x=48

4y+30=48

4y=48

y=12

b-​​ 

Let us first use the two given points: the line l2​​ passes through D and is perpendicular to l1.

Where, m1​​ represents gradient of line l1​​ and m2​​ represents gradient of line l2.​​ 

4y+3x=48

4y=-3x+48

y=-34x+484

So, m1=-3/4; therefore,​​ 

m1 x m2=-1

-34 x m2=-1

m2=43

Now, using the point-slope formula to find the equation of line l2, where point D(8, 6) & gradient​​ is m2=4/3.

y-y1=Mx-x1

y-6=43x-8

3y-18=4x-32

3y=4x-32+18

3y=4x-14

Since E is the point where l2​​ cuts y-axis so the y coordinate of E is the y-intercept of line l2.

y=4x3-143

Hence, the​​ y-coordinate of line l2​​ is -14/3.

c-​​ 

Using the formula of arc length of a sector.

l=rθ

Here the trickest part is to find the radius. The (vertical) distance between C and E is equal to radius of the sector.

r=12--143

r=363+143

r=503

Now, applying the formula of arc length.

l=rθ

l=503 x 1.8

l=30 

d-​​ 

Area of CBED=Area of sector+Area of 

Since the traingle CDE is a right angle triangle, using the formula of area as 1/2bh. The base and height is also marked on the figure below.​​ 

Base=radius=CE

Height=x-coordinate of D=6

A=12r2θ+12bh

A=12 x 5032×1.8+12503×8

A=9503 sq unit