8463/1H June 2021

  • Figure 1 shows an electric car being recharged.

i-​​ The charging station applies a direct potential difference across the battery of the car.

What does ‘direct potential difference’​​ mean?

[1 mark]

ANSWER

The potential difference is the potential difference which always remain​​ same​​ and causes current to flow in the same​​ direction, provided that the polarity of the battery remains unchanged.​​ 

 

ii-​​ Which equation links energy transferred (E), power (P) and time (t)?

[1 mark]

ANSWER

iii- The battery in the electric car can store 162 000 000 J of energy.

The charging station has a power output of 7200 W.

Calculate the time taken to fully recharge the battery from zero.

[3 marks]

SOLUTION

E=P×t 

t=162,000,0007200

t=22500 sec

iv-​​ Which equation links current (I), potential difference (V) and resistance (R)?​​ 

[1 mark]

SOLUTION

v-​​ The potential difference across the battery is 480 V.​​ 

There is a current of 15 A in the circuit connecting the battery to the motor of the​​ electric car. Calculate the resistance of the motor.​​ 

[3 marks]

SOLUTION​​ 

V=I ×R 

480=15 ×R

R= 48015

R=32

vi-​​ Different charging systems use different electrical currents.​​ 

  • Charging system A has a current of 13 A.​​ 

  • Charging system B has a current of 26 A.​​ 

  • The potential difference of​​ both charging systems is 230 V.​​ 

How does the time taken to recharge a battery using charging system A compare with the time taken using charging system B?​​ 

[1 mark]

ANSWER

To compare the time the battery took to charge, we need to compare the power​​ supplied by both the systems.​​ 

System A

P=VI

P=230×13

P=2990W

System B

P=VI

P=230×26

P=5980W

This shows us that the power supplied by B is twice greater than the power supplied by A.​​ And therefore, the time taken by system A is double than the time taken by​​ system B. This can be mathematically​​ proven as​​ 

PB=2PA

WtB=2WtA

Electrical work done by both the systems is the same as the voltage across both is 230V.

tA=2tB

So, time taken using system A is double the time of system B.​​