8463/1H June 2020

Coach Name: Sir Muhammad Abdullah Shah

8.​​ A student investigated how the total resistance of identical resistors connected in parallel varied with the number of resistors.​​ 

The student used an ohmmeter to measure the total​​ resistance of the resistors.​​ 

Figure 11​​ shows the student’s circuit with 3 resistors.

The student repeated each reading of resistance three times.​​ 

Table 1​​ shows some of the results for 3 resistors in parallel.

i-​​ Calculate value X in​​ Table 1.​​ 

[2 marks]

SOLUTION​​ 

Mean resistance=Reading 1+Reading 2+Reading 33

15.7=15.8+15.3+x3

3(15.7)=15.8+15.3+x

47.1=31.1+x

x=16

ii-​​ The student thought that taking a fourth reading would improve the precision of the results.​​ 

The fourth reading was 16.2 Ω.​​ 

Explain why the student was wrong.​​ 

[2 marks]

ANSWER

The fourth result is less precise because it is less​​ closer to the mean value than other readings.

Figure 12​​ shows the results box from the investigation.

iii-​​ The student concluded that the number of resistors in parallel was inversely proportional to the mean total resistance.​​ 

Explain why the student was​​ correct.​​ 

Use data from​​ Figure 12​​ in your answer.​​ 

[3 marks]

ANSWER

We will multiply mean total resistance and number of resistors in parallel for two separate points, if their answers​​ comes the same it can be concluded that there exist an inverse​​ proportionality between number of resitors in parallel and mean total resistance.​​ 

So, the two separate points from the graph are​​ 

(2, 24)​​ 

2×24=48

And (3, 16)

3×16=48

Now, since the product of​​ number of resitors in parallel and mean total resistance​​ at any point on the graph is a constant value, the student’s consclusion stands correct.

iv-​​ Explain why adding resistors in parallel decreases the total resistance.​​ 

[2 marks]

ANSWER

There are multiple paths for the electron flow as a result there is a greater current flowing across the circuit at the same potential difference.​​